3.1130 \(\int (A+B x) (d+e x)^2 (b x+c x^2)^3 \, dx\)

Optimal. Leaf size=225 \[ \frac{1}{8} c x^8 \left (A c e (3 b e+2 c d)+B \left (3 b^2 e^2+6 b c d e+c^2 d^2\right )\right )+\frac{1}{7} x^7 \left (3 b^2 c e (A e+2 B d)+3 b c^2 d (2 A e+B d)+A c^3 d^2+b^3 B e^2\right )+\frac{1}{6} b x^6 \left (b^2 e (A e+2 B d)+3 b c d (2 A e+B d)+3 A c^2 d^2\right )+\frac{1}{5} b^2 d x^5 (2 A b e+3 A c d+b B d)+\frac{1}{4} A b^3 d^2 x^4+\frac{1}{9} c^2 e x^9 (A c e+3 b B e+2 B c d)+\frac{1}{10} B c^3 e^2 x^{10} \]

[Out]

(A*b^3*d^2*x^4)/4 + (b^2*d*(b*B*d + 3*A*c*d + 2*A*b*e)*x^5)/5 + (b*(3*A*c^2*d^2 + b^2*e*(2*B*d + A*e) + 3*b*c*
d*(B*d + 2*A*e))*x^6)/6 + ((A*c^3*d^2 + b^3*B*e^2 + 3*b^2*c*e*(2*B*d + A*e) + 3*b*c^2*d*(B*d + 2*A*e))*x^7)/7
+ (c*(A*c*e*(2*c*d + 3*b*e) + B*(c^2*d^2 + 6*b*c*d*e + 3*b^2*e^2))*x^8)/8 + (c^2*e*(2*B*c*d + 3*b*B*e + A*c*e)
*x^9)/9 + (B*c^3*e^2*x^10)/10

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Rubi [A]  time = 0.298026, antiderivative size = 225, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 1, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.042, Rules used = {771} \[ \frac{1}{8} c x^8 \left (A c e (3 b e+2 c d)+B \left (3 b^2 e^2+6 b c d e+c^2 d^2\right )\right )+\frac{1}{7} x^7 \left (3 b^2 c e (A e+2 B d)+3 b c^2 d (2 A e+B d)+A c^3 d^2+b^3 B e^2\right )+\frac{1}{6} b x^6 \left (b^2 e (A e+2 B d)+3 b c d (2 A e+B d)+3 A c^2 d^2\right )+\frac{1}{5} b^2 d x^5 (2 A b e+3 A c d+b B d)+\frac{1}{4} A b^3 d^2 x^4+\frac{1}{9} c^2 e x^9 (A c e+3 b B e+2 B c d)+\frac{1}{10} B c^3 e^2 x^{10} \]

Antiderivative was successfully verified.

[In]

Int[(A + B*x)*(d + e*x)^2*(b*x + c*x^2)^3,x]

[Out]

(A*b^3*d^2*x^4)/4 + (b^2*d*(b*B*d + 3*A*c*d + 2*A*b*e)*x^5)/5 + (b*(3*A*c^2*d^2 + b^2*e*(2*B*d + A*e) + 3*b*c*
d*(B*d + 2*A*e))*x^6)/6 + ((A*c^3*d^2 + b^3*B*e^2 + 3*b^2*c*e*(2*B*d + A*e) + 3*b*c^2*d*(B*d + 2*A*e))*x^7)/7
+ (c*(A*c*e*(2*c*d + 3*b*e) + B*(c^2*d^2 + 6*b*c*d*e + 3*b^2*e^2))*x^8)/8 + (c^2*e*(2*B*c*d + 3*b*B*e + A*c*e)
*x^9)/9 + (B*c^3*e^2*x^10)/10

Rule 771

Int[((d_.) + (e_.)*(x_))^(m_.)*((f_.) + (g_.)*(x_))*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> In
t[ExpandIntegrand[(d + e*x)^m*(f + g*x)*(a + b*x + c*x^2)^p, x], x] /; FreeQ[{a, b, c, d, e, f, g, m}, x] && N
eQ[b^2 - 4*a*c, 0] && IntegerQ[p] && (GtQ[p, 0] || (EqQ[a, 0] && IntegerQ[m]))

Rubi steps

\begin{align*} \int (A+B x) (d+e x)^2 \left (b x+c x^2\right )^3 \, dx &=\int \left (A b^3 d^2 x^3+b^2 d (b B d+3 A c d+2 A b e) x^4+b \left (3 A c^2 d^2+b^2 e (2 B d+A e)+3 b c d (B d+2 A e)\right ) x^5+\left (A c^3 d^2+b^3 B e^2+3 b^2 c e (2 B d+A e)+3 b c^2 d (B d+2 A e)\right ) x^6+c \left (A c e (2 c d+3 b e)+B \left (c^2 d^2+6 b c d e+3 b^2 e^2\right )\right ) x^7+c^2 e (2 B c d+3 b B e+A c e) x^8+B c^3 e^2 x^9\right ) \, dx\\ &=\frac{1}{4} A b^3 d^2 x^4+\frac{1}{5} b^2 d (b B d+3 A c d+2 A b e) x^5+\frac{1}{6} b \left (3 A c^2 d^2+b^2 e (2 B d+A e)+3 b c d (B d+2 A e)\right ) x^6+\frac{1}{7} \left (A c^3 d^2+b^3 B e^2+3 b^2 c e (2 B d+A e)+3 b c^2 d (B d+2 A e)\right ) x^7+\frac{1}{8} c \left (A c e (2 c d+3 b e)+B \left (c^2 d^2+6 b c d e+3 b^2 e^2\right )\right ) x^8+\frac{1}{9} c^2 e (2 B c d+3 b B e+A c e) x^9+\frac{1}{10} B c^3 e^2 x^{10}\\ \end{align*}

Mathematica [A]  time = 0.0825138, size = 225, normalized size = 1. \[ \frac{1}{8} c x^8 \left (A c e (3 b e+2 c d)+B \left (3 b^2 e^2+6 b c d e+c^2 d^2\right )\right )+\frac{1}{7} x^7 \left (3 b^2 c e (A e+2 B d)+3 b c^2 d (2 A e+B d)+A c^3 d^2+b^3 B e^2\right )+\frac{1}{6} b x^6 \left (b^2 e (A e+2 B d)+3 b c d (2 A e+B d)+3 A c^2 d^2\right )+\frac{1}{5} b^2 d x^5 (2 A b e+3 A c d+b B d)+\frac{1}{4} A b^3 d^2 x^4+\frac{1}{9} c^2 e x^9 (A c e+3 b B e+2 B c d)+\frac{1}{10} B c^3 e^2 x^{10} \]

Antiderivative was successfully verified.

[In]

Integrate[(A + B*x)*(d + e*x)^2*(b*x + c*x^2)^3,x]

[Out]

(A*b^3*d^2*x^4)/4 + (b^2*d*(b*B*d + 3*A*c*d + 2*A*b*e)*x^5)/5 + (b*(3*A*c^2*d^2 + b^2*e*(2*B*d + A*e) + 3*b*c*
d*(B*d + 2*A*e))*x^6)/6 + ((A*c^3*d^2 + b^3*B*e^2 + 3*b^2*c*e*(2*B*d + A*e) + 3*b*c^2*d*(B*d + 2*A*e))*x^7)/7
+ (c*(A*c*e*(2*c*d + 3*b*e) + B*(c^2*d^2 + 6*b*c*d*e + 3*b^2*e^2))*x^8)/8 + (c^2*e*(2*B*c*d + 3*b*B*e + A*c*e)
*x^9)/9 + (B*c^3*e^2*x^10)/10

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Maple [A]  time = 0.001, size = 240, normalized size = 1.1 \begin{align*}{\frac{B{c}^{3}{e}^{2}{x}^{10}}{10}}+{\frac{ \left ( \left ( A{e}^{2}+2\,Bde \right ){c}^{3}+3\,B{e}^{2}b{c}^{2} \right ){x}^{9}}{9}}+{\frac{ \left ( \left ( 2\,Ade+B{d}^{2} \right ){c}^{3}+3\, \left ( A{e}^{2}+2\,Bde \right ) b{c}^{2}+3\,B{e}^{2}{b}^{2}c \right ){x}^{8}}{8}}+{\frac{ \left ( A{c}^{3}{d}^{2}+3\, \left ( 2\,Ade+B{d}^{2} \right ) b{c}^{2}+3\, \left ( A{e}^{2}+2\,Bde \right ){b}^{2}c+{b}^{3}B{e}^{2} \right ){x}^{7}}{7}}+{\frac{ \left ( 3\,A{d}^{2}b{c}^{2}+3\, \left ( 2\,Ade+B{d}^{2} \right ){b}^{2}c+ \left ( A{e}^{2}+2\,Bde \right ){b}^{3} \right ){x}^{6}}{6}}+{\frac{ \left ( 3\,A{d}^{2}{b}^{2}c+ \left ( 2\,Ade+B{d}^{2} \right ){b}^{3} \right ){x}^{5}}{5}}+{\frac{A{b}^{3}{d}^{2}{x}^{4}}{4}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((B*x+A)*(e*x+d)^2*(c*x^2+b*x)^3,x)

[Out]

1/10*B*c^3*e^2*x^10+1/9*((A*e^2+2*B*d*e)*c^3+3*B*e^2*b*c^2)*x^9+1/8*((2*A*d*e+B*d^2)*c^3+3*(A*e^2+2*B*d*e)*b*c
^2+3*B*e^2*b^2*c)*x^8+1/7*(A*c^3*d^2+3*(2*A*d*e+B*d^2)*b*c^2+3*(A*e^2+2*B*d*e)*b^2*c+b^3*B*e^2)*x^7+1/6*(3*A*d
^2*b*c^2+3*(2*A*d*e+B*d^2)*b^2*c+(A*e^2+2*B*d*e)*b^3)*x^6+1/5*(3*A*d^2*b^2*c+(2*A*d*e+B*d^2)*b^3)*x^5+1/4*A*b^
3*d^2*x^4

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Maxima [A]  time = 0.989138, size = 327, normalized size = 1.45 \begin{align*} \frac{1}{10} \, B c^{3} e^{2} x^{10} + \frac{1}{4} \, A b^{3} d^{2} x^{4} + \frac{1}{9} \,{\left (2 \, B c^{3} d e +{\left (3 \, B b c^{2} + A c^{3}\right )} e^{2}\right )} x^{9} + \frac{1}{8} \,{\left (B c^{3} d^{2} + 2 \,{\left (3 \, B b c^{2} + A c^{3}\right )} d e + 3 \,{\left (B b^{2} c + A b c^{2}\right )} e^{2}\right )} x^{8} + \frac{1}{7} \,{\left ({\left (3 \, B b c^{2} + A c^{3}\right )} d^{2} + 6 \,{\left (B b^{2} c + A b c^{2}\right )} d e +{\left (B b^{3} + 3 \, A b^{2} c\right )} e^{2}\right )} x^{7} + \frac{1}{6} \,{\left (A b^{3} e^{2} + 3 \,{\left (B b^{2} c + A b c^{2}\right )} d^{2} + 2 \,{\left (B b^{3} + 3 \, A b^{2} c\right )} d e\right )} x^{6} + \frac{1}{5} \,{\left (2 \, A b^{3} d e +{\left (B b^{3} + 3 \, A b^{2} c\right )} d^{2}\right )} x^{5} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((B*x+A)*(e*x+d)^2*(c*x^2+b*x)^3,x, algorithm="maxima")

[Out]

1/10*B*c^3*e^2*x^10 + 1/4*A*b^3*d^2*x^4 + 1/9*(2*B*c^3*d*e + (3*B*b*c^2 + A*c^3)*e^2)*x^9 + 1/8*(B*c^3*d^2 + 2
*(3*B*b*c^2 + A*c^3)*d*e + 3*(B*b^2*c + A*b*c^2)*e^2)*x^8 + 1/7*((3*B*b*c^2 + A*c^3)*d^2 + 6*(B*b^2*c + A*b*c^
2)*d*e + (B*b^3 + 3*A*b^2*c)*e^2)*x^7 + 1/6*(A*b^3*e^2 + 3*(B*b^2*c + A*b*c^2)*d^2 + 2*(B*b^3 + 3*A*b^2*c)*d*e
)*x^6 + 1/5*(2*A*b^3*d*e + (B*b^3 + 3*A*b^2*c)*d^2)*x^5

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Fricas [A]  time = 1.31952, size = 676, normalized size = 3. \begin{align*} \frac{1}{10} x^{10} e^{2} c^{3} B + \frac{2}{9} x^{9} e d c^{3} B + \frac{1}{3} x^{9} e^{2} c^{2} b B + \frac{1}{9} x^{9} e^{2} c^{3} A + \frac{1}{8} x^{8} d^{2} c^{3} B + \frac{3}{4} x^{8} e d c^{2} b B + \frac{3}{8} x^{8} e^{2} c b^{2} B + \frac{1}{4} x^{8} e d c^{3} A + \frac{3}{8} x^{8} e^{2} c^{2} b A + \frac{3}{7} x^{7} d^{2} c^{2} b B + \frac{6}{7} x^{7} e d c b^{2} B + \frac{1}{7} x^{7} e^{2} b^{3} B + \frac{1}{7} x^{7} d^{2} c^{3} A + \frac{6}{7} x^{7} e d c^{2} b A + \frac{3}{7} x^{7} e^{2} c b^{2} A + \frac{1}{2} x^{6} d^{2} c b^{2} B + \frac{1}{3} x^{6} e d b^{3} B + \frac{1}{2} x^{6} d^{2} c^{2} b A + x^{6} e d c b^{2} A + \frac{1}{6} x^{6} e^{2} b^{3} A + \frac{1}{5} x^{5} d^{2} b^{3} B + \frac{3}{5} x^{5} d^{2} c b^{2} A + \frac{2}{5} x^{5} e d b^{3} A + \frac{1}{4} x^{4} d^{2} b^{3} A \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((B*x+A)*(e*x+d)^2*(c*x^2+b*x)^3,x, algorithm="fricas")

[Out]

1/10*x^10*e^2*c^3*B + 2/9*x^9*e*d*c^3*B + 1/3*x^9*e^2*c^2*b*B + 1/9*x^9*e^2*c^3*A + 1/8*x^8*d^2*c^3*B + 3/4*x^
8*e*d*c^2*b*B + 3/8*x^8*e^2*c*b^2*B + 1/4*x^8*e*d*c^3*A + 3/8*x^8*e^2*c^2*b*A + 3/7*x^7*d^2*c^2*b*B + 6/7*x^7*
e*d*c*b^2*B + 1/7*x^7*e^2*b^3*B + 1/7*x^7*d^2*c^3*A + 6/7*x^7*e*d*c^2*b*A + 3/7*x^7*e^2*c*b^2*A + 1/2*x^6*d^2*
c*b^2*B + 1/3*x^6*e*d*b^3*B + 1/2*x^6*d^2*c^2*b*A + x^6*e*d*c*b^2*A + 1/6*x^6*e^2*b^3*A + 1/5*x^5*d^2*b^3*B +
3/5*x^5*d^2*c*b^2*A + 2/5*x^5*e*d*b^3*A + 1/4*x^4*d^2*b^3*A

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Sympy [A]  time = 0.110345, size = 303, normalized size = 1.35 \begin{align*} \frac{A b^{3} d^{2} x^{4}}{4} + \frac{B c^{3} e^{2} x^{10}}{10} + x^{9} \left (\frac{A c^{3} e^{2}}{9} + \frac{B b c^{2} e^{2}}{3} + \frac{2 B c^{3} d e}{9}\right ) + x^{8} \left (\frac{3 A b c^{2} e^{2}}{8} + \frac{A c^{3} d e}{4} + \frac{3 B b^{2} c e^{2}}{8} + \frac{3 B b c^{2} d e}{4} + \frac{B c^{3} d^{2}}{8}\right ) + x^{7} \left (\frac{3 A b^{2} c e^{2}}{7} + \frac{6 A b c^{2} d e}{7} + \frac{A c^{3} d^{2}}{7} + \frac{B b^{3} e^{2}}{7} + \frac{6 B b^{2} c d e}{7} + \frac{3 B b c^{2} d^{2}}{7}\right ) + x^{6} \left (\frac{A b^{3} e^{2}}{6} + A b^{2} c d e + \frac{A b c^{2} d^{2}}{2} + \frac{B b^{3} d e}{3} + \frac{B b^{2} c d^{2}}{2}\right ) + x^{5} \left (\frac{2 A b^{3} d e}{5} + \frac{3 A b^{2} c d^{2}}{5} + \frac{B b^{3} d^{2}}{5}\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((B*x+A)*(e*x+d)**2*(c*x**2+b*x)**3,x)

[Out]

A*b**3*d**2*x**4/4 + B*c**3*e**2*x**10/10 + x**9*(A*c**3*e**2/9 + B*b*c**2*e**2/3 + 2*B*c**3*d*e/9) + x**8*(3*
A*b*c**2*e**2/8 + A*c**3*d*e/4 + 3*B*b**2*c*e**2/8 + 3*B*b*c**2*d*e/4 + B*c**3*d**2/8) + x**7*(3*A*b**2*c*e**2
/7 + 6*A*b*c**2*d*e/7 + A*c**3*d**2/7 + B*b**3*e**2/7 + 6*B*b**2*c*d*e/7 + 3*B*b*c**2*d**2/7) + x**6*(A*b**3*e
**2/6 + A*b**2*c*d*e + A*b*c**2*d**2/2 + B*b**3*d*e/3 + B*b**2*c*d**2/2) + x**5*(2*A*b**3*d*e/5 + 3*A*b**2*c*d
**2/5 + B*b**3*d**2/5)

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Giac [A]  time = 1.16377, size = 394, normalized size = 1.75 \begin{align*} \frac{1}{10} \, B c^{3} x^{10} e^{2} + \frac{2}{9} \, B c^{3} d x^{9} e + \frac{1}{8} \, B c^{3} d^{2} x^{8} + \frac{1}{3} \, B b c^{2} x^{9} e^{2} + \frac{1}{9} \, A c^{3} x^{9} e^{2} + \frac{3}{4} \, B b c^{2} d x^{8} e + \frac{1}{4} \, A c^{3} d x^{8} e + \frac{3}{7} \, B b c^{2} d^{2} x^{7} + \frac{1}{7} \, A c^{3} d^{2} x^{7} + \frac{3}{8} \, B b^{2} c x^{8} e^{2} + \frac{3}{8} \, A b c^{2} x^{8} e^{2} + \frac{6}{7} \, B b^{2} c d x^{7} e + \frac{6}{7} \, A b c^{2} d x^{7} e + \frac{1}{2} \, B b^{2} c d^{2} x^{6} + \frac{1}{2} \, A b c^{2} d^{2} x^{6} + \frac{1}{7} \, B b^{3} x^{7} e^{2} + \frac{3}{7} \, A b^{2} c x^{7} e^{2} + \frac{1}{3} \, B b^{3} d x^{6} e + A b^{2} c d x^{6} e + \frac{1}{5} \, B b^{3} d^{2} x^{5} + \frac{3}{5} \, A b^{2} c d^{2} x^{5} + \frac{1}{6} \, A b^{3} x^{6} e^{2} + \frac{2}{5} \, A b^{3} d x^{5} e + \frac{1}{4} \, A b^{3} d^{2} x^{4} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((B*x+A)*(e*x+d)^2*(c*x^2+b*x)^3,x, algorithm="giac")

[Out]

1/10*B*c^3*x^10*e^2 + 2/9*B*c^3*d*x^9*e + 1/8*B*c^3*d^2*x^8 + 1/3*B*b*c^2*x^9*e^2 + 1/9*A*c^3*x^9*e^2 + 3/4*B*
b*c^2*d*x^8*e + 1/4*A*c^3*d*x^8*e + 3/7*B*b*c^2*d^2*x^7 + 1/7*A*c^3*d^2*x^7 + 3/8*B*b^2*c*x^8*e^2 + 3/8*A*b*c^
2*x^8*e^2 + 6/7*B*b^2*c*d*x^7*e + 6/7*A*b*c^2*d*x^7*e + 1/2*B*b^2*c*d^2*x^6 + 1/2*A*b*c^2*d^2*x^6 + 1/7*B*b^3*
x^7*e^2 + 3/7*A*b^2*c*x^7*e^2 + 1/3*B*b^3*d*x^6*e + A*b^2*c*d*x^6*e + 1/5*B*b^3*d^2*x^5 + 3/5*A*b^2*c*d^2*x^5
+ 1/6*A*b^3*x^6*e^2 + 2/5*A*b^3*d*x^5*e + 1/4*A*b^3*d^2*x^4